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Theory/Dynamics

Dynamics · Chapter 06

Newton's Laws and Free Body Diagrams

Newton's Laws and Free Body Diagrams detailed theory study guide for Physics.

27 min read · 5 topics

01

Key Concepts

Key concepts will be added here.

02

Examples

Examples will be added here.

03

Introduction to Newton's Laws and Free Body Diagrams

Welcome to Newton's Laws and Free Body Diagrams. Content to be added.

04

Newton's Three Laws of Motion

Newton's Laws: The Foundation

Building upon the concepts of inertia, mass. Force, Sir Isaac Newton formulated three fundamental laws that form the bedrock of classical mechanics. These laws provide a comprehensive framework for analyzing the relationship between forces and motion.

Newton's First Law (Law of Inertia)

This law formalizes the concept of inertia we discussed earlier.

A body remains at rest or in uniform straight-line motion unless acted upon by a net external force.

Essentially, the First Law states that an object's velocity remains constant (which includes the case of zero velocity, i.e. being at rest) if, and only if, the net force acting on it is zero. If the net force is zero, the acceleration is zero. This reinforces that force is required to change velocity (i.e. to accelerate), not merely to maintain it. For example, a book of mass 0.5 kg resting on a table (v⃗=0\vec{v} = 0v=0) stays at rest unless someone applies a net force to push or lift it. Similarly, a hockey puck of mass 0.1 kg sliding on near-frictionless ice (v⃗=constant\vec{v} = \text{constant}v=constant) will continue sliding at that constant velocity in a straight line until a net force (like friction with rougher ice, collision with a wall, or air resistance) acts upon it.

True or False: For an object moving at constant velocity, Newton's First Law requires the net external force to be zero..

Newton's Second Law (Law of Acceleration)

While the First Law describes motion in the absence of a net force, the Second Law quantifies what happens when a net force is present.

The acceleration (a⃗\vec{a}a) of an object is directly proportional to the net external force (F⃗\vec{F}F) acting on it.

This fundamental law establishes the quantitative relationship between the net external force acting on an object, the object's mass, and the resulting acceleration. It states that the acceleration produced is directly proportional to the magnitude of the net force and in the same direction as the net force. Inversely proportional to the mass of the object. Mathematically, it is expressed as:

F⃗net=ma⃗\vec{F}_{net} = m\vec{a}Fnet​=ma

Here, F⃗net\vec{F}_{net}Fnet​ represents the vector sum of all external forces acting on the object (also known as the resultant force), mmm is the mass (inertia) of the object. a⃗\vec{a}a is the acceleration vector of the object. It is crucial to remember the vector nature of this law: the acceleration vector a⃗\vec{a}a always points in the same direction as the net force vector F⃗net\vec{F}_{net}Fnet​. This equation is the cornerstone of dynamics, allowing us to predict the motion of an object if we know the forces acting on it, or conversely, to determine the net force if we observe its acceleration. For example, if a net force of 10 N acts horizontally to the right on a 2 kg object initially at rest, the object will experience an acceleration of a⃗=F⃗net/m=(10 N, right)/(2 kg)=5 m/s2\vec{a} = \vec{F}_{net} / m = (10 \, \text{N, right}) / (2 \, \text{kg}) = 5 \, \text{m/s}^2a=Fnet​/m=(10N, right)/(2kg)=5m/s2 horizontally to the right.

True or False: According to Newton's Second Law, if the same net force is applied to two objects, the object with the larger mass will experience a larger acceleration.

Newton's Third Law (Law of Action-Reaction)

While the first two laws focus on the motion of a single object under the influence of forces, the Third Law describes the nature of the forces themselves as interactions between objects.

For every action, there is an equal and opposite reaction. That is, if object A exerts a force on object B (F⃗B←A\vec{F}_{B \leftarrow A}FB←A​), then object B simultaneously exerts a force on object A (F⃗A←B\vec{F}_{A \leftarrow B}FA←B​) such that F⃗A←B=−F⃗B←A\vec{F}_{A \leftarrow B} = -\vec{F}_{B \leftarrow A}FA←B​=−FB←A​.

This law highlights several critical points about forces:

  • Forces occur in pairs: Forces always arise from mutual interactions between two objects. You cannot have a single, isolated force.
  • Equal in magnitude: The two forces in an action-reaction pair always have exactly the same strength.
  • Opposite in direction: The two forces act along the same line but point in opposite directions.
  • Act on different objects: This is crucial! The 'action' force acts on one object. The 'reaction' force acts on the other object. Because they act on different objects, they do not cancel each other out when considering the motion of a single object.
  • Simultaneous: The action and reaction forces occur at the exact same time. There's no delay.

Consider these examples:

  • When a person of mass 60 kg pushes horizontally against a wall with a force of 50 N (action: force by person on wall), the wall simultaneously pushes back horizontally on the person with an equal force of 50 N (reaction: force by wall on person). The person might move (if on roller skates, for instance) due to the force on them, while the wall (usually) doesn't move significantly due to the force on it (because other forces, like those from the foundation, balance it).
  • When the Earth exerts a downward gravitational force on you (your weight - action: force by Earth on you), you simultaneously exert an upward gravitational force of equal magnitude on the Earth (reaction: force by you on Earth). You accelerate significantly towards the Earth because of the force on you (your mass is small), while the Earth accelerates imperceptibly towards you because of the force on it (its mass is enormous).
  • When a bat hits a baseball, the bat exerts a force on the ball (action). The ball simultaneously exerts an equal and opposite force on the bat (reaction).
  • When a rocket expels hot gas downwards (action: force by rocket on gas), the gas simultaneously exerts an equal and upward force on the rocket (reaction: force by gas on rocket), propelling it upwards.

This implies that all real forces in nature exist in pairs.

When kicking a football, is the action-reaction pair the force exerted by the foot on the ball and the equal and opposite force exerted by the ball on the foot?

Summary of Common Forces

In summary, a Force is an interaction between two objects or between an object and its environment, causing a change in the object's motion (acceleration) unless balanced by other forces. Based on our discussion of fundamental forces and common scenarios in mechanics, we will frequently encounter the following types of forces in this chapter:

  • Gravitational Force (Weight): The downward pull exerted by a large celestial body (like Earth) on an object near its surface (W⃗=mg⃗\vec{W} = m\vec{g}W=mg​).
  • Normal Force (N⃗\vec{N}N): The perpendicular contact force exerted by a surface on an object pressing against it, preventing penetration.
  • Tension Force (T⃗\vec{T}T): The pulling force transmitted through a string, rope, cable, or similar object when it is taut.
  • Friction Force (f⃗\vec{f}f​): A contact force parallel to the surface that opposes relative motion or attempted relative motion between surfaces.
  • Spring Force (F⃗spring\vec{F}_{spring}Fspring​): The restoring force exerted by a deformed spring, opposing the deformation.
05

Free Body Diagrams (FBDs)

What is a Free Body Diagram?

Newton's Second Law, F⃗net=ma⃗\vec{F}_{net} = m\vec{a}Fnet​=ma, is the central equation for solving dynamics problems. However, applying it correctly requires us to accurately identify all the external forces acting on the object or system of interest. A powerful and indispensable tool for achieving this is the Free Body Diagram (FBD).

An FBD is a simplified diagram representing a single object (or a system treated as a single entity) isolated from its surroundings. Its purpose is to clearly visualize all the external forces acting on that specific object. By focusing only on the object and the forces exerted on it by other objects or fields, we can systematically apply Newton's Second Law.

True or False: A Free Body Diagram isolates a single body. It represents all external forces acting on that body.

Steps to Construct a Free Body Diagram

Constructing an accurate FBD is often the most critical step in solving a dynamics problem. Here are the general steps:

  1. Identify the System: Clearly define the object or system of objects whose motion you want to analyze.
  2. Isolate the Body: Draw a simple representation of the object (e.g. a dot or a box), conceptually separating it from everything else (the 'environment').
  3. Draw External Forces: Identify every external object or field that interacts with your chosen body and exerts a force on it. Represent each force as a vector arrow originating from the object (or its center, for simplicity) and pointing in the correct direction. Common forces to consider include:
    • Gravitational Force (Weight, usually mg⃗m\vec{g}mg​ downwards)
    • Normal Force (N⃗\vec{N}N, perpendicular to and away from a contact surface)
    • Tension (T⃗\vec{T}T, along a string/rope, pulling away from the object)
    • Applied Forces (F⃗app\vec{F}_{app}Fapp​, explicitly mentioned pushes or pulls)
    • Friction (f⃗\vec{f}f​, parallel to a contact surface, opposing motion/tendency of motion)
    • Spring Force (F⃗spring\vec{F}_{spring}Fspring​, opposing deformation from equilibrium)
  4. Label Forces: Clearly label each force vector with an appropriate symbol (e.g. W,N,T,f,FappW, N, T, f, F_{app}W,N,T,f,Fapp​).
  5. Choose Coordinate Axes (Optional but Recommended): If applying Newton's Second Law in component form, draw a convenient set of coordinate axes (e.g. x-y axes). Often, aligning one axis with the direction of acceleration (if known) simplifies the calculations.

A common pitfall is including forces exerted by the object on its surroundings, or internal forces within a system. Remember, the FBD must only show external forces acting on the specific body being analyzed. For example, on an FBD for a block on a table, draw the weight (Earth on block) and the normal force (table on block).. You do not show the force exerted by the block on the table - that force belongs to the FBD of the table.

Example: Bottle on Table

Let's illustrate with an example: Consider a water bottle of mass m=0.5m = 0.5m=0.5 kg resting in equilibrium on a horizontal table.

Water bottle placed on surface of table, in state of rest.

We will use g≈10 m/s2g \approx 10 \, \text{m/s}^2g≈10m/s2 for simplicity.

Free Body Diagram (FBD) for the Water Bottle: The system is the water bottle. We isolate it and show the forces acting on it.

FBD of the water bottle: Shows Weight (W) downwards and Normal Force (N) by table upwards.

  • Weight (W⃗1\vec{W}_1W1​): Force exerted by the Earth on the bottle, acting vertically downwards. Magnitude W=mg=0.5 kg×10 m/s2=5 NW = mg = 0.5 \, \text{kg} \times 10 \, \text{m/s}^2 = 5 \, \text{N}W=mg=0.5kg×10m/s2=5N.
  • Normal Force (N1⃗\vec{N_1}N1​​): Force exerted by the table surface on the bottle, acting vertically upwards, perpendicular to the surface.

Since the bottle is in equilibrium (a⃗=0\vec{a} = 0a=0), applying Newton's Second Law on the bottle:

∑F=N1−W1=ma=0\sum F = N_1 - W_1 = ma = 0∑F=N1​−W1​=ma=0

Therefore, N1=W1=5 NN_1 = W_1 = 5 \, \text{N}N1​=W1​=5N. The normal force exerted by the table on the bottle is 5 N upwards.

Identifying Action-Reaction Pairs

Action-Reaction Pairs (Newton's Third Law):

  • The force of weight W⃗1\vec{W}_1W1​ (Earth on bottle) has a reaction pair: the gravitational force exerted by the bottle on the Earth (W1′W_1'W1′​ (Bottle on Earth)). This is equal in magnitude (5 N) and opposite in direction (upwards, towards the bottle).
Action-Reaction Pairs: Forces (Earth on Bottle) & (Bottle on Earth)

  • The normal force N1N_1N1​ (table on bottle) has a reaction pair: the force exerted by the bottle on the table (N1′N_1'N1′​ (bottle on table)), which is equal in magnitude (5 N) and opposite in direction (downwards).
  • Action-Reaction Pairs: Forces (Table on Bottle) & (Bottle on Table). Note W1W_1W1​ and N1N_1N1​ on the bottle are not a pair.

    Note that W1W_1W1​ and N1N_1N1​ are not an action-reaction pair, even though they are equal and opposite in this specific equilibrium case. They both act on the same object (the bottle) and arise from different interactions (gravity and contact).

    (Optional) Considering the Table: If we were to draw an FBD for the table, it would include following forces:

    FBD of the table: Shows Forces on the table

    • The force exerted by the bottle on the table (F⃗table←bottle=N1′\vec{F}_{table \leftarrow bottle} = N_1'Ftable←bottle​=N1′​), downwards (5 N).
    • The weight of the table itself (W⃗table=W2\vec{W}_{table} = W_2Wtable​=W2​), downwards.
    • The normal forces exerted by the ground on the table legs (N⃗table←ground=N2\vec{N}_{table \leftarrow ground} = N_2Ntable←ground​=N2​), upwards.

    In equilibrium, these forces on the table would also sum to zero, because of Newton's second law.

    For a block resting on a table, do the downward weight and the upward normal force constitute an action-reaction pair??

    Applying Newton's Laws with FBDs

    Once the FBD is correctly drawn, we can apply Newton's Second Law: ∑F⃗ext=ma⃗\sum \vec{F}_{ext} = m\vec{a}∑Fext​=ma. If the object is in equilibrium (at rest or moving with constant velocity), then a⃗=0\vec{a} = 0a=0, and the vector sum of forces is zero: ∑F⃗ext=0\sum \vec{F}_{ext} = 0∑Fext​=0. If the object is accelerating, the vector sum of forces equals the mass times the acceleration vector. Often, we resolve the forces and acceleration into components along the chosen coordinate axes: ∑Fx=max\sum F_x = ma_x∑Fx​=max​ and ∑Fy=may\sum F_y = ma_y∑Fy​=may​.

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